22c+16=3c^2

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Solution for 22c+16=3c^2 equation:


Simplifying
22c + 16 = 3c2

Reorder the terms:
16 + 22c = 3c2

Solving
16 + 22c = 3c2

Solving for variable 'c'.

Combine like terms: 3c2 + -3c2 = 0
16 + 22c + -3c2 = 0

Factor a trinomial.
(8 + -1c)(2 + 3c) = 0

Subproblem 1

Set the factor '(8 + -1c)' equal to zero and attempt to solve: Simplifying 8 + -1c = 0 Solving 8 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1c = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1c = 0 + -8 -1c = 0 + -8 Combine like terms: 0 + -8 = -8 -1c = -8 Divide each side by '-1'. c = 8 Simplifying c = 8

Subproblem 2

Set the factor '(2 + 3c)' equal to zero and attempt to solve: Simplifying 2 + 3c = 0 Solving 2 + 3c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + 3c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + 3c = 0 + -2 3c = 0 + -2 Combine like terms: 0 + -2 = -2 3c = -2 Divide each side by '3'. c = -0.6666666667 Simplifying c = -0.6666666667

Solution

c = {8, -0.6666666667}

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